lim x mendekati tak terhingga 9x²-2x-8 / 4x²-16
tolong dijawab kak besok dikumpulkan, terima kasih![]()
tolong dijawab kak besok dikumpulkan, terima kasih
Jawab:
9/4
Penjelasan dengan langkah-langkah:
[tex]\large\text{$\begin{aligned}&\lim_{x\to\infty}\frac{9x^2-2x-8}{4x^2-16}\\\\&=\lim_{x\to\infty}\left(\frac{9x^2-2x-8}{4x^2-16}\times\frac{\frac{1}{x^2}}{\frac{1}{x^2}}\right)\\\\&=\lim_{x\to\infty}\frac{9-\dfrac{2}{x}-\dfrac{8}{x^2}}{4-\dfrac{16}{x^2}}\\\\&=\frac{\lim\limits_{x\to\infty}9-\lim\limits_{x\to\infty}\dfrac{2}{x}-\lim\limits_{x\to\infty}\dfrac{8}{x^2}}{\lim\limits_{x\to\infty}4-\lim\limits_{x\to\infty}\dfrac{16}{x^2}}\\\\&=\frac{9-0-0}{4-0}\\\\&=\boxed{\ \bf\frac{9}{4}\ } \end{aligned}$}[/tex]
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